How to find a cube root geometrically?

If you are familiar with calculus, then there is a well know method called Newton's method. However...

y = x^(1/3) dy/dx = (1/3)x^(-2/3) = 1 / {3 [cube root of x]^2 }

About this: X[2] - X[9] 2.15450825808003 - 2.15443469003188 = 0.00007356804815 (More exactly, cbrt(...

You know that (x^a)^b == x^(ab) So [8^(1/2)]^(1/3) == 8^(1/6) So that is your answer, the cube root...

The roots of a quadratic in the form of ax^2+bx+c=0 is given by (-b+/-rt(b^2-4ac))/2a. There is no ...

The derivative of f'(x) is [d/dx(f(x)) = f'(x)]. To see the computational steps, check out http://www...

The domain of a function f(x) = cube root (x + 3 -1) is all numbers because the domain is all values...

You can find a cube root by guessing which two root numbers the number comes exactly in between. Then...

Enter the number, press ^ and enter 1/3 i.e. the cube root of 27 would be 27^(1/3)