How to find a cube root geometrically?
Find the differential of y- cube root x?
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Answer:
y = x^(1/3) dy/dx = (1/3)x^(-2/3) = 1 / {3 [cube root of x]^2 }
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y = x^(1/3) dy/dx = (1/3)x^(-2/3) = 1 / {3 [cube root of x]^2 }
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