What percentage mass of magnesium oxide is magnesium?

Magnesium Oxide experiment...?

If a students were given different amounts of Magnesium to burn to make Magnesium Oxide, would you expect the percentage of magnesium in their MgO to be different or similar? Would this have anything to do with Law of Constant Composition or something about elements chemically combined in fixed proportions by mass...? Please Answer.... Thanks Heaps :)
Answer:

%of Mg in all the oxides formed will be same because of the law of Constant composition which states that the elements combine chemically in fixed proportion by mass.

naresh v at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

%of Mg in all the oxides formed will be same because of the law of Constant composition which states that the elements combine chemically in fixed proportion by mass.

Related Q & A:

Is it normal for Magnesium Supplements to cause nausea?Best solution by Yahoo! Answers
Why is it important to have a control group in an experiment?Best solution by Yahoo! Answers
What is the role of the responding variable in a controlled experiment?Best solution by Yahoo! Answers
How long does magnesium citrate work?Best solution by Yahoo! Answers
"Calm" Magnesium w/ Calcium side effects?Best solution by Yahoo! Answers

Just Added Q & A:

How many active mobile subscribers are there in China?Best solution by Quora
How to find the right vacation?Best solution by bookit.com
How To Make Your Own Primer?Best solution by thekrazycouponlady.com
How do you get the domain & range?Best solution by ChaCha
How do you open pop up blockers?Best solution by Yahoo! Answers

For every problem there is a solution! Proved by Solucija.

Got an issue and looking for advice?
Ask Solucija to search every corner of the Web for help.
Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.