What is cross section plan?

Engineering Cross Section of Beams?

  • Hello all I was wondering if anyone could help me with the following:- I have a beam that is fixed at one end but unsupported at the other. If i apply a load on the unsupported end the beam bends. What i would like to know is this:- When no load is applied to the beam the cross section of the beam is of a particular shape. But does the cross section change once a load is applied and the beam bends? I hope this makes sense. Thank you thank you is the cross section of the beam the same shape when no load is applied as oppose

  • Answer:

    Tom, you are describing a classic cantilever beam. The cross section does not change when a load is applied and the beam bends.

tom at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

Tom, you are describing a classic cantilever beam. The cross section does not change when a load is applied and the beam bends.

Big Blue

The top of the beam is in tension (experiencing tensile stress) and the bottom of the beam is in compression (experiencing compressive stress). Hooke's Law will apply that is E = stress/strain. There will be an extension of the fibres of the material in the top of the beam, there will be contraction of the fibres of the material in the bottom of the beam. The stress varies from maximum tensile in the top to zero at the 'neutral axis' to maximum compressive at the bottom. I acknowledge the sense of your suggestion that the cross section deforms, which it of course does under these stresses. Such deformation is not taken into account in beam design. It may become evident in the case of failure. If you stress a mild steel bar to failure in tension you will see a very marked reduction in its cross section prior to failure. Have a look at this test on a mild steel bar and watch how it narrows. http://www.youtube.com/watch?v=YpmYMj92NZU Also this one: http://www.youtube.com/watch?v=5QaqwmZ7Sic&feature=related

Sean J

when we design, we usually stay within the elastic range. that means the deflected shape will bounce back to it's original shape after the load is removed. the governing law is s=Ex/L, so u can see stress has a linear relationship with displacement. and the beam's deflection is small. and the cross section remains the same cross section. however, when we design a building under earthquake, we design the beams and columns into the plastic range to save money and materials because the earthquake load is hugh and vast materials is involved. by plastic range, it means the beams is stress beyond it's elastic limit and it won't be able to recover it's original shape.

Fred Osim

when we design, we usually stay within the elastic range. that means the deflected shape will bounce back to it's original shape after the load is removed. the governing law is s=Ex/L, so u can see stress has a linear relationship with displacement. and the beam's deflection is small. and the cross section remains the same cross section. however, when we design a building under earthquake, we design the beams and columns into the plastic range to save money and materials because the earthquake load is hugh and vast materials is involved. by plastic range, it means the beams is stress beyond it's elastic limit and it won't be able to recover it's original shape.

Fred Osim

The top of the beam is in tension (experiencing tensile stress) and the bottom of the beam is in compression (experiencing compressive stress). Hooke's Law will apply that is E = stress/strain. There will be an extension of the fibres of the material in the top of the beam, there will be contraction of the fibres of the material in the bottom of the beam. The stress varies from maximum tensile in the top to zero at the 'neutral axis' to maximum compressive at the bottom. I acknowledge the sense of your suggestion that the cross section deforms, which it of course does under these stresses. Such deformation is not taken into account in beam design. It may become evident in the case of failure. If you stress a mild steel bar to failure in tension you will see a very marked reduction in its cross section prior to failure. Have a look at this test on a mild steel bar and watch how it narrows. http://www.youtube.com/watch?v=YpmYMj92NZU Also this one: http://www.youtube.com/watch?v=5QaqwmZ7Sic&feature=related

Sean J

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.