When brakes are applied, the speed of a train decreases from 96km/h to 48 km/h in 800m.how much further will t?
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Answer:
Incomplete Question. Initial speed = u = 96 km/h = 96000 m / (60*60) s = 80/3 m/s Final speed = v = 48 km/h = 48000 m / (60*60) s = 40/3 m/s distance traveled = s = 800 m Applying the formula v² = u² + 2as , where a = acceleration => a = (v² - u²)/(2s) = - (4800 / 9) / 1600 m/s² = - 1/3 m/s² further distance traveled before coming to rest = s' 0 = v² + 2as' s' = - v² / (2a) = - (40/3)² / (- 2/3) = (1600/9)*(3/2) = 800 / 3 m
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