How to find all equals paths in degenerate tree from specific start vertex?
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I have some degenerate tree (it looks like as array or doubly linked list). For example, it is this tree: Each edge has some weight. I want to find all equal paths, which starts in each vertex. In other words, I want to get all tuples (v1, v, v2) where v1 and v2 are an arbitrary ancestor and descendant such that c(v1, v) = c(v, v2). Let edges have the following weights (it is just example): a-b = 3 b-c = 1 c-d = 1 d-e = 1 Then: The vertex A does not have any equal path (there is no vertex...
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You write, in comments, that your current approach is It seems, I looking for a way to decrease constant...
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Other solutions
Buddhism for beginners (and sceptical Westerners) Introduction Now that Buddhism is such a fast-growing religion in the West, a lot of Westerners are attracted to its rational approach and rejection of an all-powerful deity. But all too often we Westerners...
Answer:
Dhamma friend, My master once told a Prof.of psychology from Cambrige U(a Buddhist as well) that he...
Thomas at Yahoo! Answers Mark as irrelevant Undo
I heard the Nodes symbolize past lives and in this case, it may be true. His sun conjuncts my North Node and his Moon conjuncts my South Node. Also, his 7th House is in Gemini. My vertex is in Taurus. Him: Asc. Sagittarius Sun Pisces 5.51 Moon Virgo...
Answer:
WOW.....This made me cry a little bit....because it reminds me soooo much of my own current non - existent...
feisty pants at Yahoo! Answers Mark as irrelevant Undo
Let G be an undirected graph, and let u and v be two distinct, nonadjacent vertices in G. Two paths from u to v are intermediate-vertex-disjoint if the only vertices that these paths share are u and v. Give an algorithm that efficiently finds a largest...
Answer:
You can solve this using max flow. First you split each node x in two nodes x1 and x2. All edges going...
Cosmin Negruseri at Quora Mark as irrelevant Undo
My husband and I are in our early 30's. He is in a big hurry to start a family, believes that our window of time is rapidly closing and feels that soon it will be too late. I am not ready for this, and do not share his sense of urgency. I've told him...
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I have been in the place of not having close friends with kids and agonizing over whether and when to...
keep it under cover at Ask.Metafilter.Com Mark as irrelevant Undo
Something like this - Sorry about the bad paint drawing. So I have the above paths. They are relatively close to each other or you can say follow the same pattern. How do I find the mean path?
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Let's say you have four paths, p, q, r and s. If the paths are "time-stamped" (parametrized...
Jun-Geun Park at Quora Mark as irrelevant Undo
From research, this is what I concluded on how to start a bonsai from a seed. Plant seed in ground. For 3 years only water and feed, just like a garden plant. After three years, uproot the tree and prune the roots. Then, put the tree in a very small...
Answer:
Kindly click on the links below(There are two closely related to bonsai ) ; they will open a number...
Joshua at Yahoo! Answers Mark as irrelevant Undo
From research, this is what I concluded on how to start a bonsai from a seed. Plant seed in ground. For 3 years only water and feed, just like a garden plant. After three years, uproot the tree and prune the roots. Then, put the tree in a very small...
Answer:
It all depends on what type of tree/plant you're working with. You cut back the roots when they outgrow...
Joshua at Yahoo! Answers Mark as irrelevant Undo
In the book Cracking the coding interview the answer is only considering subset of paths from root to leaf whereas the solution can span the entire diameter of the tree. The 'path' can start from the left subtree through root to the right subtree.
Vikas Veshishth at Quora Mark as irrelevant Undo
Let G(V,E)G(V,E)G(V,E) be a directed graph with positive weights on its edges, and let s∈Vs∈Vs \in V be a node. Suggest an algorithm that in time O((|V|+|E|)log|V|)O((|V|+|E|)logâ¡|V|)O((|V| + |E|) \log |V|) time algorithm...
Answer:
Run Dijkstra's algorithm in the reverse graph of GGG, where sss is the source. The edges of the shortest...
Bidhan Roy at Quora Mark as irrelevant Undo
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