How can I convert a string number to a number in Perl?

Beginner at C# Stuck on convert to question?

• Im starting to write c# in VCE and in a console application static void Main(string[] args) { double firstNumber, secondNumber; string userName; Console.WriteLine(″Enter your name:″); userName = Console.ReadLine(); Console.WriteLine(″Welcome {0}!″, userName); Console.WriteLine(″Now give me a number:″); firstNumber = Convert.ToDouble(Console.ReadLine()); Console.WriteLine(″Now give me another number:″); secondNumber = Convert.ToDouble(Console.ReadLine()); Console.WriteLine(″The sum of {0} and {1} is {2}.″, firstNumber, secondNumber, firstNumber + secondNumber); Console.WriteLine(″The result of subtracting {0} from {1} is {2}.″, secondNumber, firstNumber, firstNumber - secondNumber); Console.WriteLine(″The product of {0} and {1} is {2}.″, firstNumber, secondNumber, firstNumber * secondNumber); Console.WriteLine(″The result of dividing {0} by {1} is {2}.″, firstNumber, secondNumber, firstNumber / secondNumber); Console.WriteLine(″The remainder after dividing {0} by {1} is {2}.″, firstNumber, secondNumber, firstNumber % secondNumber); Console.ReadKey(); } So why I am using double at beginning when I am declaring the vars? And then what exaclty is the convert to double doing. Maybe I just dont understand what the converting is doing. I understand it when you convert a INT to a string....I dunno

• Answer:

  I haven't used C# in a while, so forgive me if my terminologies aren't quite correct or exact. The difference between the variable types "int" and "double": An int is a 32-bit whole number, with no decimal points. A double is a 64-bit number and is decimal point capable. Console.ReadLine() is a Function that allows the user to type something in, in string form. The output or value of the function is whatever string the user entered. On line 8 the program asks the user for a number, to be saved under the double "firstNumber." This is so at the end of the program the numbers can be applied mathematically, where a string would not be able to. However, you can't store a string in a double variable without converting it first. So that's where the function "Convert.ToDouble()" comes in. The input is of string type, and the output is of double type. So to recap, here's line 9 written in plain English: firstNumber (a decimal point capable variable) = (is set to the value of): the user's input (string format), after being converted into decimal number format. If there's anything we didn't address, or you're looking for more details, please feel free to drop a line on our Facebook page.