Converting char array to double in C?

How to malloc an array of char pointers?

• Hi Right now I have this: char *files[ 20 ]; I then use my array: files[ i ] = whatever; And it works as I want it to. However I want the size of the array to be dynamic, so i tried: char *files; ... files = ( char * ) malloc( array_size * ( sizeof( char ) ); ...but this doesn't seem to work. What's the correct way to convert "char *files[20]" to something of a dynamic size?

• Answer:

  In C, [] is very similar to *. So, char *files[20] gives you 20 pointers, each to a character or an array of characters. Similarly, char **files gives you a pointer to one or more pointers to one or more characters. So, use this: char **files = (char **)malloc(arraySize*sizeof(char *)); This means that file is a pointer to an array of character pointers. Allocate an array of character pointers. In both the *files[20] and the **files cases, be sure to initialize the 20 or the arraySize pointers.