how to write makefile for python?

WHAT IS WRONG WITH MY PYTHON SCRIPT!?

• I am following along with a tutorial on how to make a webserver. I am using python 2.7.2 and this is the code #!/usr/bin/env python # import sys for handling command line argument # import socket for network communications import sys, socket # hard-wire the port number for safety's sake # then take the names of the host and file from the command line port = 80 host = sys.argv[1] filename = sys.argv[2] # create a socket object called 'c' c = socket.socket(socket.AF_INET, socket.SOCK_STREAM) # connect to the socket c.connect((host, port)) # create a file-like object to read fileobj = c.makefile('r', 0) # Ask the server for the file fileobj.write("GET "+filename+" HTTP/1.0\n\n") # read the lines of the file object into a buffer, buff buff = fileobj.readlines() # step through the buffer, printing each line for line in buff: print line I keep getting the error sys.argv[1] list index out of range What am i doing wrong?

• Answer:

  how are you calling your program? from the command line? Sounds like you didn't give it a value, therefore that indexed position was never created. Should be something like this: ./myFile.py myHost remoteFile