How to call functions inside a function in Python?

Python: What's the best way to get the script to call a function from user input?

• I have a script with many function each called problemx() where x is a number from 1 upwards i.e problem1(), problem2(), etc. It's difficult to explain the question but let me just show you. while True: ....user = raw_input('problem(blank to exit): ') ....if user == '': ........break ....else: ........user = int(user) ........if user == 1: ............problem1() ........elif user == 2: ............problem2() ........elif user == 3: ............problem3() ........elif user == 4: ............problem4() ........elif user == 5: ............problem5() ........elif user == 6: ............problem6() That's just some of it, it goes on for a while, lol @ the pun... anyways, how do you get it to call a function without actually coding it like the above, for example converting the user input into somekind of code literal or something, I don't even know what I'm saying but hopefully you know what I mean. It seems a trivial problem but I have a lot of ideas that are faced with this problem. Thanks for any help or pointers.

• Answer:

  For python 2.7: while True: user = raw_input('Problem no. (break to quit) -> ') if user == '': break else: try: int(user) except: print 'That isn\'t an integer' else: user = int(user) if user in range(1, 6): eval('problem%s()' %(user)) Here's the full script I wrote, plus explanatory comments: http://pastebin.com/uij2eGeY For python 3.x, you simply need to use print() instead of print ' ', and use input() instead of raw_input(), like this: http://pastebin.com/QA0xS3hg