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How do I open a window from the outside?

How do I specify window size in a window.open operation?

  • function openWindow(srcFile) { window.open(srcFile,'newWnd','width=800,… } I want to open a popup window, but I can only specify the dimensions manually, is there any way to insert a variable into the parameter string ie function openWindow(srcFile, srcWidth, srcHeight) { window.open(srcFile,'newWnd','width=*src… } thanks!

  • Answer:

    Take a look at the example in this site. http://www.devguru.com/Technologies/ecmaScript/quickref/win_open.html To pass height and width value to the function you do -: function openWindow(srcWidth, srcHeight) { mywindow=window.open("", "tinyWindow", 'toolbar,width=' +srcWidth +',height=' + srcHeight); } copy and paste this code and try it out to see the result hope this helps

ryandebr... at Yahoo! Answers Visit the source

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window.open("page.html","width=600, height=400, scrollbars=yes");

rob

in javascript you can refrence variables by using a terminated constant and the plus opperator for example: "mike" + " roth" = Mike Roth so you can then do it through that mechanism by setting the third parameter as 'width=' + width + ',height=' + height

Michael R

You will find other examples at this web site as well, if this is not the programming language you wanted

Lue

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