How do you use Van der Waals forces to rank intermolecular forces?
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Based on the given van der Waals constants, arrange these hypothetical gases in order of decreasing strength of intermolecular forces. Assume that the gases have similar molar masses. Q: a= 5.46 b= 0.0305 D: a= 4.16 b= 0.0373 M: a= 2.25 b= 0.0428 R: a= 1.34 b= 0.0322 Please explain how to solve it!
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Answer:
The higher the a value, the stronger the intermolecular attraction. So, the strongest attraction would be Q, followed by D, then M, and R would be the weakest.
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