Functional Groups in Aspartame? Chemistry?

A few Organic Chemistry Questions?

  • personally, i'm not good with organic chemistry. -_- so can someone help me with this by explaining this? >_< or at least try to. haha. 1. Briefly discuss the following statement: "The functional group concept is important in organizing the information of organic chemistry." Support your discussion by using two chemical equations to illustrate the application of this concept for each of two functional groups. 2. Draw structural formulas for SEVEN different ISOMERS of C3H4Cl2. 3. Write the structural formulas for two stable isomers X and Y that have the molecular formula C2H4O2. Select a physical property and a chemical property that would distinguish between the two isomers in the laboratory. Explain. 4. Dehydration of 3-hexanol yields a mixture of four isomers each with the molecular formula C6H12. Draw structures of the four isomers and name each of them. PLEASE help me... ._. please help and explain before Sunday PLEASE. I will be so grateful to anyone who helps. :] thanks!

  • Answer:

    lol...these questions are easy (5 minutes to answer) but typing structural formulas in this format is difficult (>one hour!). . 1, Not sure I understand the question. but... Functional groups determine the properties and reactions of organic cmpnds to a large extent. Eg, 'heavy' atoms such as Cl tend to increase boiling point; hydrophilic groups such as OH can increase sol in water. Alcohols can be esterified by acids, whereas ethers cannot ROH + R*COOH-->R*COOR ROR** + R*COOH...no reaction Amines form salts, whereas nitro cmpnds cannot RNH3 + HCl-->RNH3.HCl RNO2 + HCl...no reaction (Is this what teach wants?...you find more examples.) 2. (X is for Cl, to avoid confusion with C) CH2=CH-CHX2... CH2=CX-CH2X... CHX=CH-CH2X CX2=CH-CH3... CHX=CX-CH3 CH2 CHX-CHX CH2 CH2-CX2 These are triangular...draw bonds connecting all carbons...bot will not allow better depiction. 3. X is acetic acid CH3COOH Y is methyl formate HCOOCH3 X solidifies sl below RT(if pure), Y boils sl above RT X is neutralized by a base (eg titrating w NaOH), Y is neutral 4. CH2=CHCH2CH2CH2CH3 1-hexene CH3CH=CHCH2CH2CH3 2-hexene CH3CH2CH=CHCH2CH3 3-hexene (CH2)6...draw as a ring... cyclohexane (note -ane, not -ene) Hope this is not simply an easy way to get your homework done...at least study the answers to learn something...you're on your own in a test remember.

sooper mouse! at Yahoo! Answers Visit the source

Was this solution helpful to you?

Other answers

1. FUNCTIONAL GROUP [functional group] in organic chemistry, group of atoms within a molecule that is responsible for certain properties of the molecule and reactions in which it takes part. Organic compounds are frequently classified according to the functional group or groups they contain. For example, methanol, ethanol, and isopropanol are all classified as alcohols since each contains a functional hydroxyl group. The accompanying table shows important functional groups and the classes of compounds in which they occur. look here for further explanation... http://en.wikipedia.org/wiki/Functional_group 2.ClCH=CH-CH2Cl ClCH=CCl-CH3 CH2=CH-CHCl2 CH2=CCl-CH2Cl Cl2C=CH-CH3 1,1-dichlorocyclopropane 1,2-dichlorocyclopropane 3.CH3COOH carboxylic acid CH2OHCOH alcohol and aldehyde 4.cyclohexane, 1=hexene, 2-hexene, 3-hexene best answer?

teroy

I am off to bed

taketwo

Number 2; isomers; structures with the same chemical formula, but different arrangement of atoms. This venue is not possible for this kind of work, so get to structuring and rearranging,or type in isomer in your address bar.

jonmcn49

Related Q & A:

Just Added Q & A:

Find solution

For every problem there is a solution! Proved by Solucija.

  • Got an issue and looking for advice?

  • Ask Solucija to search every corner of the Web for help.

  • Get workable solutions and helpful tips in a moment.

Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.