Calculate the temperature at which NH4Cl (s) will begin to spontaneously decompose?
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calculate the temperature at which NH4Cl (s) will begin to spontaneously decompose into NH3 (g) and HCl (g) at one atmosphere pressure. The reaction is NH4Cl (s) ---> HCl (g) + NH3 (g) assume ΔH° and ΔS° are temprature independent
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Answer:
The sad part is that you didn't provide what the enthalpy and entropy actually are. So my answer is that I do not know, but use G=H-TS and solve for T when G equals 0.
Jake at Yahoo! Answers Visit the source
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