How do u find the heat exchange, specific heat of a metal, and molar mass of a metal?
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In this experiment a hot metal block at 100oC is added to cold water in a calorimeter. The heat lost by the metal block equals the heat gained by the water and the two end up at the same temperature. In one experiment, the mass of the metal block is 107 grams, the volume of water used is 72.0 mL, the temperature of the cold water extrapolated to the time of mixing is 18.4oC, and the temperature of the metal block and water extrapolated back to the time of mixing is 27.6oC. The specific heat of water is 4.184 J K-1g-1 How much heat is gained by the cold water? Heat gained by cold water = J What is the specific heat of the metal? Specific heat of the metal = J K-1g-1 According to the Law of Dulong and Petit, what is the molar mass of the metal? Molar mass = g mol-1
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Answer:
assuming denity water = 1g/mL mass water = 72.0 g heat gained by water = 72.0 x 4.184 ( 27.6 - 18.4)= 2771 J 107 x specific heat ( 27.6 - 100) + 2771=0 specific heat = 0.358 J/g°C convert the specific heat in J/Kg°C specific heat = 3 R/ M M is the molar mass hope this helps
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