How many grams of sodium carbonate are present after the reaction is complete? ?
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Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.20 grams of sodium carbonate is mixed with one containing 4.57 grams of silver nitrate.
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Answer:
2 AgNO3 & 1 Na2CO3 --> Ag2CO3 & 2 NaNO3 using the ratio that reacts, & molar masses ... find the g Na2CO3 that react: 4.57 g AgNO3 @ (105.99 g/mol Na2CO3) / (2 mol AgNO3)(169.88 g/mol) = 1.4256 grams of Na2CO3 react find How many grams of Na2CO3 are present after the reaction: 3.20 grams - 1.4256 g Na2CO3 react = 1.774 grams remain your answer(3sigfigs): 1.77 g Na2CO3 remain
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