Heat Capacity of Calorimeter? PLZZZZZZZ Help!?
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A student adds 46.7 g of water to a calorimeter and allows the temperature to stabilize in a thermostat bath at 25.00°C. Next, s/he adds 43.8 g of 100.0°C water. The final temperature of the entire apparatus comes to 49.3°C. What is the effective heat capacity of the calorimeter in J/°C? Take the specific heat capacity of water as 4.184 J g-1°C-1 Hint: heat is lost by the hot water; heat is gained by both the cold water and the calorimeter. Express the answer in the form ±x.xxE±x
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Answer:
heat lost by hot water = m*c*t ( mass* sp heat cap* temp diff) = 43.8* 4.184*(100- 49.3) J heat gained by water= 46.7* 4.184* (49.3-25) J heat gained by calorimetre = mass? * c * (49.3-25) mass of calorimetre is not given in the problem without which the prob cant be solved. heat lost by hot water = heat gained by cold water plus calorimetre sp heat cap of calorimetre = (heat lost by hot water - heat lost by cold water)/ mass of calorimetre * temp diff of calorimetre
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