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The specific heat capacity of lead is 0.128 J·mol-1·K-1. Find its molar heat capacity.?

• can anyone help me with these chemistry questions. Thank you 1. The specific heat capacity of lead is 0.128 J·mol-1·K-1. Find its molar heat capacity. 2. From the specific heat capacity given above, find the amount of energy which must be supplied to raise the temperature of a 0.500 g piece of lead by 75 K. 3. Calculate the specific heat capacity of copper given that 1.20 kJ of energy raises the temperature of 25.0 g of copper from 25°C to 150°C.

• Answer:

  I'm not sure your question is correct. Specific heat capacity is measured in J/g*K and molar heat capacity is in J/mol*K... It looks like you've been given the molar heat capacity. Anyway to convert from specific heat (J/g*K) to molar heat capacity (J/mol*K) of a substance just multiply specific heat capacity by its molar mass (g/mol). The molar mass for lead is 207.2100 g/mol. Example similar to 1.: Specific heat capacity of water at 25 deg.C = 4.1813 J/g*K and its molar mass = 18.01 g/mol Therefore water's molar heat capacity at 25 deg. C is (4.1813 J/g*K)(18.01 g/mol) = (75.30 J/mol*K) 2. The equation needed in this problem is q=CΔT. q is the amount of heat (which is a form of energy) which is what you're looking for, C is heat capacity measured in J/K and ΔT is the change in temp. With that information you should be able to do it on your own. Just remember that specific heat is given in terms of J/g*K... so how would you convert that value into J/K? Unit conversion! Always remember your units. 3. Using the same equation as above q=CΔT, do some simple algebra to solve for C which is what they ask for this time. C=q/ΔT. q is measured in J - again, remember unit conversions, and ΔT is still in K. With this info you should be able to get it! Good luck.