How do i find the empirical formula of a compound?
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That has 10g Cu and 2.52g O2? How do I find the molar ratio so I can find out which one is the limiting reactant?
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Answer:
Moles Cu atoms = 10/ 63.5 =0.1575 Moles O atoms = 2.52/16 = 0.1575 Dividing by least no. Cu = 0.1575/ 0.1575 = 1 O = 0.1575/ 0.1575 = 1 Empirical formula CuO
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