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Solve the following equation for X. Remember to balance the equation?

Ionic equation!! Help to solve it. Break it to oxidation and reduction equation and balance it please?

  • MnO4- + SO2 + H+ = SO42- + Mn2+ + H2O Sorry i cant do the superscript and subscript. Need help with this. The questions asks me to break it into oxidation and reduction. And balance it also. It says it is in acid media

  • Answer:

    MnO4- & 8 H+ & 5 electrons --> Mn2+ & 4 H2O a reduction of Mn+7 in MnO4- into Mn+2, a change in oxidation # of 5) SO2 & 2 H2O --> (SO4)-2 & 4H+ & 2 electrons (an oxidation of S+4 in SO2 into S+6 in (SO4)-2 , a change in oxidation # of 2) to balance the electrons taken & loss: 2 MnO4- & 16 H+ & 10 electrons --> 2 Mn2+ & 8 H2O 5 SO2 & 10 H2O --> 5 (SO4)-2 & 20 H+ & 10 electrons giving: 2 (MnO4)- & 5 SO2 & 2 H20 = 5 (SO4)2- & 2 Mn2+ & 4 H+ balance oxygens, yes 20/20 balance hydrogens, yes 4/4 charges balance, yes -2/ -2 that's your answer

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