ALREADY SOLVED, PLS CHECK: How many ul of H202 in 20 ml solvent to make a 20 mM H202 solution?
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I'm given Molar mass 34.0147 g/mol Density 1.463 g/ cm3 So moles = mass/ molar mass 20/1000 moles = mass / 34.0147 g/mol so 0.6803 g h202 needed in 1 L of solution for a 20 mM solution 0.6803 g converted to ml is mass/volume = density 0.6803 g/ 1.463 g/ml = 0.464 ml of h202 in 1 L solution for 20 mM h202 solution. then i only need 20 ml of that 1 L solution, so its 0.464 /50 = 0.0092 mL or 9.2 ul of h202 on 20 ml solution for a 20 mM h202 solution
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Answer:
looks good to me
Ms. Chanandler Bong at Yahoo! Answers Visit the source
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