Use Hess's law to calculate ΔH for the reaction below. N2(g) + 2 O2(g) 2 NO2(g)?
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Consider the following data. N2(g) + O2(g) 2 NO(g) ΔH = +180.7 kJ 2 NO(g) + O2(g) 2 NO2(g) ΔH = -113.1 kJ 2 N2O(g) 2 N2(g) + O2(g) ΔH = -163.2 kJ Use Hess's law to calculate ΔH for the reaction below. N2(g) + 2 O2(g) 2 NO2(g) ΔH = ?kJ
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Answer:
You only need to use the first two equations. NO is a catalyst because it is a product in the first and a reactant in the second. Canceling it out, you get the reaction you want. All you have to do now is add the delta H for the first to reactions together. delta H = 180.7 - 113.1 = 67.6 kJ
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