What is the molecular weight of a gas that has a mass of 2.18 grams per Liter?
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This one is playing on my vocab I think. Its asking me the weight of a weight. Do I multiply (22.4L/mol)(2.18g/l) and end up with 48.8 g/mol?
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Answer:
1 mole of gas occupies 22.4 L in 1 L of gas we have 1/22.4 M or 0.04464 moles these weigh 2.18 g so 1 mole weighs 2 .18 / .04464 g / mole or 48.8g
Kim J at Yahoo! Answers Visit the source
Other answers
There is not really enough information given in the problem. The pressure and temperature of the gas should also be given, But if you assume STP conditions, you did the problem correctly.
Fred
Molecular weight would be the mass of 1 molecule of the gas. You have solved for molar weight which is the mass of 6.022 x 10^23 molecules of the gas: Assuming STP (22.4L/mol)(2.18g/L)(1mol/6.022 x 10^23molecules) = 8,11 x 10^-23g/molecule
NutrtionalAdvice
Yes try it.
600pm
You can always go back to PV=nRT for both STP and non-STP conditions. PV=nRT remember n=g/MolWt PV= (g/MolWt)RT rearrange the equation P(MolWt)=(g/L)RT more rearranging MolWt = (g/L)RT/P now you know g/L,R,T,P so solve for the molwt
Peter Boiter Woods
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