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How to find the empirical formula?

How would I find the Empirical formula of this compound? ?

  • I'm so confused on this question. If you could please just guide me in setting up the question, i will greatly appreciate it! Here's the question: A sample of chlorine oxide gas reacts with excess hydrogen to produce 0.3059 g of HCL and 0.5287 g of water. What is the empirical formula of Chlorine oxide gas?

  • Answer:

    moles HCl = 0.3059 / 36.461 g/mol =0.008390 = moles Cl in the oxide Moles H2O = 0.5287 g / 18.02 g/mol = 0.02934 => moles O in the oxide Cl 0.008390 O 0.02934 we divide by the smallest number Cl O 3.5 to get whole numbers we multiply by 2 Cl2O7 is the formula

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