Calculate the rate of the reaction when 5.1×10−2M.?
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The following reaction is first order in N2O5 (g) ---> NO3 (g) + NO2 (g) The rate constant for the reaction at a certain temperature is 0.053.
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Answer:
A rate law with one reactant is written as: Rate = k[A]^m m = 1 because the reaction is first order. [A]=[N2O5]=(5.1 x 10^-2 M) rate constant = k So... Rate = (0.053)(5.1 x 10^(-2))^1 I hope that that helps.
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no thats cheating do it yourself :)
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