Describe how you would prepare 2.00 L of each of the following solutions?
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a. 0.100 M K2CrO4 from solid K2CrO4 b. 0.100 M K2CrO4 from 1.75 K2CrO4 stock solution
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Answer:
0.100 M = moles / 2.00 moles K2CrO4 = 0.200 194.19 g/mol x 0.200 mol =38.8 g of K2CrO4 + enought water to reach the volume of 2.00 L 0.100 x 2.00 = 1.75 V2 V2 = 0.114 L 114 mL of stock solutio + enought water to reach the volume of 2.00 L
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