What was the molar concentration of acetic acid in the vinegar?

HELP Please !!! Vinegar / Acetic Acid Titration with NaOH - To Calculate Mass and Volume - PLEASE HELP !!!?

• In the lab we used 3ml of vinegar solution, titrated with 12.15 ml NaOH. Concentration of NaOH used was 0.09846M . We have to calculate the following: 1. Moles of NaOH required to reach the equivalence point? 2. Moles of acetic acid 5.0 ml of vinegar? 3. Mass of acetic acid in 5 ml sample of vinegar? 4. Volume of the acetic acid in the 5 ml sample of vinegar? 5. % by volume of acetic acid in the vinegar? Please HELP . I have to submit it in the morning, and I have no idea how to calculate these :( I have been trying for hours, but can't figure it out...

• Answer:

  Based on the official monograph of acetic acid from USP each mL of 0.1M of NaOH is equivqlent to 6.005mg acetic acid from this we can calculate mass of acetic in 5mL vinegar 12.15mL x 6.005mg/mL moles of acetic acid wt of acetic in g / MW acetic acid MW acetic = 60.05g/mol moles of NaOH = moles of acetic acid volume of acetic acid mass of acetic / density of acetic acid density acetic = 1.049 % volume volume of acetic acid / 5mL enjoy tour problem!!!