What are the hybrid orbitals of CO2?

Reaction 1: NaHCO3(s) → NaOH(s) + CO2(g) Reaction 2: NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) ....?

• Please help!<3 I have no idea what I am doing. Reaction 1: NaHCO3(s) → NaOH(s) + CO2(g) Reaction 2: NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) Reaction 3: NaHCO3(s) → Na2O(s) + CO2(g) + H2O(g) Suppose in the lab you heated 5.00 g of baking soda and, after the decomposition, determined that 3.41 g of solid product was formed. Given this data, which of the following unbalanced equations would you choose? Make this choice by minimizing the percent error for the mass of the product. Note: this is not necessarily the correct equation for the reaction, nor is it necessarily what you chose in the lab – it is the best choice given the data in this problem. NaHCO3(s) → NaOH(s) + CO2(g) NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) NaHCO3(s) → Na2O(s) + CO2(g) + H2O(g)

• Answer:

  Okay, all the reactions have the same reactant: NaHCO3(s), so because we have 5.00 grams of reactant, we can calculate the number of moles of product by calculating the molar mass. Na = 22.99 H = 1.008 C = 12.01 O = 16.00 So 22.99+1.008+12.01+3(16.00) = 84.008 - Molar mass of baking soda To convert the grams to moles we do: 5.00 grams baking soda (1 mol baking soda/ 84.00 grams baking soda) = .05953 moles baking soda. next balance the equations to get: 1st one is balanced 2 NaHCO3 --> Na2CO3 + CO2 + H2O 2NaHCO3 --> Na2O + 2CO2 + H2O the stoichiometric coefficients between the reactant and the solid products in the first reaction is a 1:1 ratio and the molar mass of NaOH = 22.99+1.008+16.00 = 40.00 so .05953 moles (1 mole product/1 mole baking soda)(40.00 grams product/1 mole product) = 2.381 grams For the next two reactions the stoichiometric coefficient is 2:1 So now we calculate the molar mass of Na2CO3 and Na2O Na2CO3 = 22.99+22.99+12.01+3(16.00) = 106.0 Na2O = 61.98 Now we again do the stoichiometery .05953 mols (1 mole Na2CO3/2 moles baking soda)(106.0 grams Na2CO3/1mol) = 3.155 and .05953 moles (1 mol Na2O/ 2 mole baking soda)( 61.98/1mol) = 1.844 So the reaction with the lowest percent error is reaction 2 with Na2CO3