What is the volume occupied by carbon dioxide if 0.98 mol of the gas exerts a pressure of 1.5 atm at 22°C?
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Assume real gas behavior.
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Answer:
This has all the components of The Ideal Gas Law PV =nRT P=pressure V=volume n- moles R= constant 0.0821 ( L )(atm) / (K)(mol) T= temp in K or kalvin ( K= C+ 273.15) So, you have been GIVEN: P = 1.5 atm V = ? n = 0.98 mol R = 0.0821 ( L )(atm) / ( K )(mol) T= 22C First, convert the C to K: K = C + 273.15 K = 22C + 273.15 K + 295.15 Now, solve for V: PV=nRT V = nRT / P V = [ (0.98 mol) {(0.0821 (L )(atm)( K )(mol)} ( 295.15 K ) ] ----------------------------------------… 1.5 atm V = 15.83145 L
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