How can I enter into the IT field after 30?

The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field?

• The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 6.65 x 106 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.46 x 10-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were (a) an electron and (b) a proton. (a) __________ m (b) __________ m

• Answer:

  The force on the particle due to the magnetic field is: F = qvB where q = charge, v = speed and B = magneitc field strength and assumes v is pependicular to B The centripital force the particle experiences is: Fc = mv^2/r where r = radius of orbit around the field line Now F = Fc sine the particle spirals around the field line so: mv^2/r = qvB ---> solve for r ----> r = qB/(mv) Use m= 9.11x10^-31 kg for the electron and m = 1.6x10^-27 kg for the proton and you're done