How do I calculate the strain in a roller coaster? (Physics)?
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I calculate the stress using this: Stress (Force per area)= ((84 people x 70 kilograms) x (9.81 metres per second per second x 3))/(0.900 metres) Stress (Force per area)= 173,049/0.900 = 192,277 Pascals But I'm not sure what to do to calculate the strain, because I don't know how to get the extension!
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Answer:
Perhaps consult a stress-strain curve for the given material (steel?). If there is no permanent deformation the strain will occur on the linear portion of the curve.
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Other answers
stress = force / Area Force is in Newton (g m/s^2) Area in m^2 convert kg to newton = 1 x 10^3 x 9.81 =9.81 x 10^3 if each person weights 70 kg ( 70*9.81x10^3)*84 = 57.68 x 10^6 N ( i dont know why you times it by 3) assuming you have made an error in your calculation. Area = 0.9 m thus stress = (57.68 x 10^6 N) / (0.9 m^2) = 64.09 x 10^6 N/m^2 N/m^2 = 1 pascal Now to workout the strain you need the young's modulus of the material.. for steel is normally (29 x10^6) Young's modulus E = stress / strain thus strain = stress /E = (57.68 x 10^6)/(29x10^6) = 1.99 dimensionless strain = change in length / original length .. if you know the original length you can workout the change in length.. Always check your units.. It's very important.. you wont make mistakes
Jarih
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