How do i find the the derivative of the inverse of a function?
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the function is y=x+(1/x) at y=17/4 once again, i need to find the derivative of the inverse of y. (the math section didn't answer)
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Answer:
Swap X and Y to get the inverse function: x = y + y^-1 Then use implicit differentiation: 1 = y' - y'/y^2 = y'(1 - 1/y^2) Thus y' = 1 / (1 - 1/y^2) = y^2 / (y^2 - 1) Evaluating at y=17/4 gives y' = 289/273
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