Determine the kinetic energy of a 625- kg roller coaster car that is moving with a spped of 18.3 m/s.?
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()Determine the kinetic energy of a 625- kg roller coaster car that is moving with a spped of 18.3 m/s.? (2) If the roller coaster in problem no. 1 were moving with twice the spped, then what would be its new kinetic energy... please answer this
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Answer:
(1)K.E (kinetic energy) = 1/2 * m * v^2 =1/2 * 625 * 18.3 * 18.3 =104653.125 Joules =1.05kJ (2) from KE=1/2*mv^2, if v were doubled (i.e, x2) would be x4. (since 2^2=4) so 4*104653.125 Joules =418612.5 Joules =4.19 kJ
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Other answers
New Kinetic energy = 0.5*0.625*(2*18.3)^2 = 418.6125 J
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