If the first string is playing at 103 Hz how far off in frequency is the second string?
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String instrument players can tune one string off of another - once you are happy with the tension and resulting pitch in one lower string, you put your finger down partway up the first string at the appropriate spot to make a higher pitch, one which should match the fundamental pitch of the next string over. If the second string is almost, but not quite properly tuned, you will hear beats. Suppose you are doing this, and hear one beat every 0.96 s when trying to adjust the second string. If the first string (with your finger on it) is playing at 103 Hz how far off in frequency is the second string? Note that this frequency for the first string might not match a standard guitar, perhaps it's a more unusual string instrument! (Find the answer in Hz, but do not enter units. If you think the second string is 5 Hz off, answer 5.0.)
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Answer:
I hope this is as simple as I think it is. The beat frequency equals the difference in the two frequencies = 1 beat / 0.96s = 1.04 Hz So the second string is just 1.04 Hz off in frequency. ANS: 1.04
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