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PhysicsII problem: What potential difference between the plates would give an energy density of .089J/m^3?

  • The problem states it's a parallel-plate air capcitor made using two plates .07m square, spaced 3.4mm apart. What must the potential difference between the plates be to produce an energy density of .089 J/m^3 ?

  • Answer:

    for a parallel plate capacitor the energy is U = (1/2) C V^2 or U /v = (1/2) C V^2 / v, where 'v' is the volume ie., energy density U/v = (1/2) (eoA/d ) V^2 / A d = (1/2) eo V^2 / d^2 0.089 = (1/2) x8.854x10^-12 x V^2 / 3.4x3.4x10^-6 or V^2 = 2 x 0.089 x 3.4x3.4 x10^-6 / 8,854x10^-12 = 232401 or potential difference V = 482 volt.

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