Why is tangential acceleration different from acceleration due to gravity? (UCM problem)?
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Radius of Earth: 6371 km Period of Earth's rotation: 24 h Tangential acceleration in UCM = v^2/r For tangential acceleration, I received 0.033 ms^-2 I checked this answer with others and it seems correct. Why is the acceleration provided in this answer based on the Earth's radius and velocity different from the acceleration due to gravity which is 9.81ms^-2? v^2= [(2*pi*r)/T]^2 a=[(4*pi^2*r)/T^2] a=4*pi^2*6371km/24h^2 a=0.033ms^-2
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Answer:
Given you're taking tangential acceleration at the earth's surface, why should it be equal to the acceleration due to gravity? Whatever the thing in question is, object or person, it would be of no weight when in contact with the earth and we know that isn't generally the case. If my answer doesn't suffice, maybe you should clarify the question.
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