How can I enter into the IT field after 30?

Consider the mass spectrometer shown schematically in Figure P19.30. The electric field between the plates...?

• Consider the mass spectrometer shown schematically in Figure P19.30. The electric field between the plates of the velocity selector is 900 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.930 T. Calculate the radius of the path in the system for a singly charged ion with mass m = 2.18 10-26 kg. (Hint: The figure is of a mass spectrometer. Charged particles are first sent through a velocity selector. They then enter a region where a magnetic field 0 (directed inward) causes positive ions to move in a semicircular path and strike a photographic film at P) m http://www.webassign.net/sercp/p19-30.gif

• Answer:

  Hello Bradley, first with E and B we can get v as E/B So v = 900/0.930 m/s For radius R = mv / Bq We need m. It is given. q = 1.6 *10^-19 C and v is found and B is already there. Please plug and simplify by yourself dear. As the electric power has gone here I could not work out in details.