How to do a ski jump?

A ski jumper of mass 100 kg is at the top of the ski jump.?

• A ski jumper of mass 100 kg is at the top of the ski jump. The end of the jump is 40 meters below his starting position. Assuming no friction, what will be his speed at the end of the jump? The ground is 90 meters below his starting position, what is his speed when he hits the ground?

• Answer:

  To do this, assuming there is no friction, I would use the Law of Energy Conservation with the Gravitational Potential and Kinetic energy equations. At the Top. Et=Eg =mgh =(100)(9.8)(40) =39200J At the Jump Et=Ek =(1/2)mv² 39200=(1/2)(100)v² v=28m/s At Top Et=Eg =mgh =(100)(9.8)(90) =88200J At Bottom Et=Ek =(1/2)mv² 88200=(1/2)(100)v² v=42m/s This is an alternate way of doing the ski jump, it uses the same principles though. At the Jump Et=Eg+Ek =mgh+1/2mv² 88200=(100)(9.8)(50)+50v² v=28m/s