How to move the object to the position of mouse(opengl?

The position of an object moving in a straight line is given by s=2t^2 - 3t..?

• The position of an object moving in a straight line is given by s=2t^2 - 3t, where 's' is in meters and 't' is the time in seconds the object has been in motion. How long (to the nearest tenth) will it take the object to move 8 meters? A) 2.9 sec 9.0 sec C) 0.7 sec D) 10.4 sec A ladder is resting against a wall. The top of the ladder touches the wall at a height of 18ft. Find the length of the ladder if the length is 6ft more than its distance from the wall. A) 24 ft 36 ft C) 30 ft D) 18 ft I 7x-4 I -1 > -9 A (-4/7, infinity) B (-4/7, 12/7) C (-infinity, infinity) D no solution square root of 2x+5 - square root of x-2=3 A 2 B 2, 38 C -2 D 3,8 square root of x+6 + square root of 2-x+4 A 2,-2 B 0 C -2 D square root of 31, -2

• Answer:

  I will do the first couple: s=2t^2 - 3t if s=8, we have the quadratic equation 2t^2-3t=8 2t^2-3t-8=0 solve using quadratic equation methods and get t=2.9s the second one is a pythagorean theorem problem the height is 18; call the base d, then the hypotenuse is d+6 we have then 18^2+d^2=(d+6)^2 18^2+d^2=d^2+12d+36 288=12 d d=24, so the length is 30