How strong is the sun gravitational pull?

Why don't we feel the Sun's gravity pull?

  • I am a student currently studying for a degree in aerospace engineering I have asked several teachers and many other people the following question but have not received any respectable answer: The Earth is 93 million miles from the sun. Other planets, and even much denser planets I might add, are much further yet from the sun. The obviously strong gravitational attraction of the sun holds all of these planets in orbits around the sun. If gravity could be simply defined as a force that attracts matter, and the sun's gravitational pull is sufficient to hold the Earth in orbit, what keeps it from pulling me off the Earth? In fact, the gravitational pull of the sun is so weak at this distance that It can't even produce enough pull to raise a hair on my head. So how can it hold the Earth and several even denser planets (even further out) in orbit? So--if the gravitational force of the sun is powerful enough to hold the Earth in orbit, then how could the Earth's gravitational force be powerful enough to hold me down, counter-acting the gravitational force of the sun? Please unconfuse me!

  • Answer:

    The Earth's gravitation force is powerful enough because the equation for gravity is squared. That squared factor is the difference. Gravity = Mass times distance squared. If you double the distance from the object, you lessen it's gravitation force upon you by a factor of 4. If you triple your distance from an object, you lessen it's gravitation force upon you by a factor of 9. If you increase the distance by a factor of 10, the gravitation force is lessened by a factor of 100. Now think of this when you consider your distance from the Sun compared to your distance from Earth. The Sun is not 93 million times larger than the earth, and you commonly not more than 93 million microns from Earth, never mind 93 million miles. So, determine the number of microns in 93 million miles and then square that number. Then create a fraction with the digit 1 about that number in the numerator, while that number is in the denominator. For example (1/999,999,999,999,999,999,999,999). This is not the actual answer, but it is the comparable force of the graviational pull of the Sun on you compared to the Earth. That is not going to lift a hair off your head, or pull the free floating atmosphere away from planet Earth. The Lagrange points ( the points in outer space when the gravitation pull of the Sun equals the graviational pull of the Earth are very close to Earth. Study the Lagrange points for more information. You do not have to travel very far from Earth to find the points in space where the graviational force of the Sun is equal to the graviational force of the Earth. Then you say, why doesn't the Sun just pull the Earth into it. The Sun does not pull the Earth into it, because the Earth is in motion around the Sun. If the Earth were to stop rotating around the Sun, the Earth would be pulled into the Sun. Just as if the Space shuttle stopped traveling 18,000 miles per hour around the Earth, it would be pulled back into the earth. If you do not believe me, study the re-entry speed of SpaceShip One recently. This is all basic Newtonian gravity. Any good science teacher would know this.

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That does sound confusing and it is a very good question. I remember studying that in school, but darn if I remember. It has to do with our gravitational pull --here on Earth as you stated. Our planet is special. Think of the moon and others that have no gravity and you just drift off into space --supposedly. Plus the sun is soooooooo far away. Our planet was created with gravity and that is what keeps us from being enough to hold us down. Think of the other planets too--their weather and their unlivable conditions. Maybe that has something to do with why they aren't like Earth.

just julie

You won't feel the gravity because we are in orbit around the Sun with the Earth and the gravity is balanced by centripetal force. However what you could feel and measure is the Sun's tidal force which is really the difference in the Sun's gravity from the center of the Earth to the surface of the Earth. This force causes half of our tides. The other half is caused by the Moon. More equations would be necessary to explain all this.

rscanner

Well without the ability to draw formulas here it is harder to explain...but go look at the formula for gravitational force. Here's one: http://scienceworld.wolfram.com/physics/GravitationalForce.html The key point is that you'll notice one term is of higher power than the others and it happens to be in the denominator. Put simply, it means this term can grow very rapidly and this term happens to be r, the distance between the two bodies under test. So when you consider the distance between you and the earth as compared to the sun and the earth you should see why the force of the sun on you is too small for you to perceive. So why does it have such a big effect on the earth then? Now look at the definitions of the terms in the numerator. Two of the terms are the masses of the bodies involved. Now since the mass of the sun is the same for both test cases, this leaves only your mass (and the earth's) to be considered. Just consider the MAGNITUDE of difference between your mass and the earth's and it becomes apparent why the force exerted on the earth is significant enough to cause it to orbit the sun.

fathead

In physics, for a given gravitational field and a given position, the escape velocity is the minimum speed an object without propulsion, at that position, needs to have to move away indefinitely from the source of the field, as opposed to falling back or staying in an orbit within a bounded distance from the source. The object is assumed to be influenced by no forces except the gravitational field; in particular there is no propulsion, as by a rocket, there is no friction, as between the object and the Earth's atmosphere (these conditions correspond to freefall) and there is no gravitational radiation. This definition may need modification for the practical problem of two or more sources in some cases. In any case, the object is assumed to be a point with a mass that is negligible compared with that of the source of the field, usually an excellent approximation. It is commonly described as the speed needed to "break free" from a gravitational field. One somewhat counterintuitive feature of escape velocity is that it is independent of direction, so that "velocity" is a misnomer; it is a scalar quantity and would more accurately be called "escape speed". The simplest way of deriving the formula for escape velocity is to use conservation of energy, thus: in order to escape, an object must have at least as much kinetic energy as the increase of potential energy required to move to infinite height. Defined a bit more formally, "escape velocity" is the initial speed required to go from an initial point in a gravitational potential field to infinity with a residual velocity of zero, relative to the field. Conversely, an object starting at rest and at infinity, dropping towards the attracting mass, would reach its surface moving at the escape velocity. In common usage, the initial point is on the surface of a planet or moon. On the surface of the Earth the escape velocity is about 11.2 kilometres per second. However, at 9000 km altitude in "space", it is slightly less than 7.1 km/s. The escape velocity from the surface of a rotating body depends on direction in which the escaping body travels. For example, as the Earth's rotational velocity is 465 m/s to the east at the equator, a rocket launched tangentially from the Earth's equator to the east requires an initial velocity of about 10.735 km/s relative to earth to escape whereas a rocket launched tangentially from the Earth's equator to the west requires an initial velocity of about 11.665 km/s relative to earth. The surface velocity decreases with the cosine of the geographic latitude, so space launch facilities are often located as close to the equator as feasible, e.g. the American Cape Canaveral in Florida and the European Centre Spatial Guyanais, only 5 degrees from the equator in Guyana. --------------------------------------… Gravity is the most important force that governs the motion of the Earth through space. It also keeps the moon in orbit around the Earth, and the Earth and all of the other planets in orbit around the sun. Scientists have learned that gravity also governs the motion of the sun in the Milky Way. They believe that it is probably the major factor in explaining the origin of the galaxies, the stars, and the planets. The force of gravity is a two-way affair. The sun exerts a gravitational force upon the Earth to keep it in orbit. The Earth exerts an equal—but opposite—force upon the sun. Gravitational forces between the Earth and the moon interact in much the same way. The camera helps astronauts share experiences with the world. This spectacular view of the cloudy … NASA The moon's gravity affects the whole planet Earth. Just as the moon swings around the Earth because of the Earth's gravity, so the Earth—to a smaller extent—swings around the moon because of the moon's gravity. The difference in the extent of the swing results from differences in the mass and distance. The Earth's mass is 81 times as great as that of the moon. So as the moon swings one way in its orbit around the Earth, the Earth swings 1/81 as far in an answering orbit around the moon. The actual center of rotation for the Earth-moon system is about 500 miles (800 kilometers) below the Earth's surface. Imagine a gigantic pin stuck through the Earth, about parallel with the Earth's true axis but about 3,500 miles (5,600 kilometers) from it—just barely through the edge of the Earth. The Earth and the moon rotate about this pin. The center of the Earth is in balance with the gravitational attraction of the moon. The moon's effect complicates the Earth's motion. The Earth does not move in a smooth path around the sun but has a monthly “wobble” in its joint orbit with the moon. (See also gravitation.) The moon's gravity causes daily ocean tides on both sides of the Earth. On the side nearer to the moon, the gravity effect is stronger, so a bulge of water is pulled out on that side. Conversely, on the side away from the moon, the effect is weaker, and a bulge of water extends outward, away from the moon. (See also ocean waves and tides.) The sun also affects the tides. Sun tides, much smaller than moon tides, result from the interaction of gravity between the sun and the Earth. Twice a month the tidal effects of the sun and moon are combined. The Earth's highest and lowest tides occur then. The rocky body of the Earth itself has tides. These Earth tides are much smaller than the ocean tides and can be measured only with delicate instruments that were specially designed to measure these tides.

Ask Dr. Dingo

Remember that the Earth is in orbit around the sun. That means that the centrifugal force from the orbit matches the gravitational force from the sun. Technically, we are also in orbit around the sun, so that same balance happens for us. Given that, the next strongest force is that of the earth's gravity. We are *not* in orbit around the earth, so there isn't a balance there.

mathematician

Do you remember how astronauts in a space craft orbiting around the Earth are weightless? This is because they are in a state of constant free fall. They have no weight because there is nothing of equal and opposite force to press them against a scale. For the same reason why there is no weight from the Earth on the Astronaut as they orbit the Earth, there is no gravity of the sun affecting your weight here on earth.

eric l

Gravity is based on two aspects. One is the mass of the two objects in question. Second is the distance between those two objects. The distance factor is actually squared, so even though the sun is many times more massive, its distance squared makes the gravitational effect on a person neglible. However, the sun's gravitational effect does show itself in another phenomenon. It affect the tides that the earth's oceans undergo. If the sun and the moon are lined up with the earth (full or new moons), tides will be measurably higher or lower than when the moon is at an angle (1st and 3rd quarter moons)

the sun IS pulling on you, and moving you, along with the earth, in a nearly circular "fall" around it (at least that's one way of looking at it). The sun is certainly having a strong gravitational effect on you and me and the earth at the same time, anyway. why don't you feel it? well, the force is pretty much constant, and the acceleration due to gravity is what keeps us going AROUND the sun rather than off in a straight line. so it just feels "normal" as far as the gravitational force of earth vs sun goes, the earth is just so much nearer that it pulls us back down every time we try to jump off. but just get close enough to the sun (more than half the distance from sun to earth) and you will find the sun's gravity stronger, and be pulled inexorably towards it unless some rescue team interferes to bring you back

artful dodger

because earth's gravity is stronger where you are and so it pulls you toward the earth. the suns gravity does pull you but it has less energy than the earth.

iammisc

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