ELECTRIC POTENTIAL, POTENTIAL ENERGY & WORK DONE BY THE ELECTRIC FIELD. Urgent..... need the solution...?
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Two point charges +3.0x10^-6C and + 6.0x10^-6C are separated by 1.20m in vaccum as inthe Figure 2 below: +3.0x10^-6C M + 6.0x10^-6C I-------------------I----------------I <----------------><-------------> 0.60cm 0.60cm a) Find the resultant electric potential mid-way between the two charges. b) Determine the work done to bring a positive charge of 0.2μC from infinity to the mid-way point between the two point charges. (Ans : 13.5x104V/C, 2.7x10^-2J)
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Answer:
a) Electric potential is a scalar. Sum up the potential due to each charge So ∑V = kq₁/r + kq₂/r = k/r [q₁ + q₂] = (9•10⁹)/(0.6•10⁻²) [9μC] = 13.5•10⁴ V b) Note that ΔU = qΔV = 0.2μC (13.5•10⁴ V) = 2.7•10⁻² V Yin
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