On a still lake, the speed of a motorboat is 24m/s. however, the operator of this boat wants to cross a river?
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on a still lake, the speed of a motorboat is 24m/s. however, the operator of this boat wants to cross a river that is 88m wide and flowing at 15m/s. since he wants to reach the point directly across the river, he attempts to compensate for the flow of the river by pointing the boat in a direction of 35 degrees upstream from the direction that is straight across the river. when the boat reaches the other side of the river, how far is it from the desired destinatioin, and is it upstream or downstream from the destination?
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Answer:
The boat will land 5.5 meters downstream from the desired destination. (Answer) Break it into velocity components. The boat's speed directly across the river is 24 cos 35°, and it's upstream velocity is 24 sin 35°. The river's downstream velocity is 15 m/s, so the net is 24 sin 35° - 15. It takes 88 / (24 cos 35°) seconds to cross the river, so the placement on the other side is (24 sin 35° - 15) net m/s [88 / (24 cos 35°)] sec = 88 tan 35° - 55 sec 35° = -5.5 m downstream. (Answer)
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Other answers
15 - 24sin35 = 1.234 m/s = horizontal speed of the boat (downstream) 24cos35 = vertical speed of the boat t = 88/24cos35 = 4.476s 1.234 * 4.476 = 5.52 answer 5.52m downstream
Julian
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