The perimeter of a rectangle is 18cm. whats its greatest possible area?area of rectangle 36cm2 least perimeter
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the area of a rectangle is 18cm whats its greatest possible area? another ? ummm...the area of a rectangle is 36cm2 whats its least possible perimeter? SMART PEOPLE HELP ME PLZ!!!! I WILL LOVE YOU FOR EVER!!! Email me if you want 2 talk
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Answer:
For the first, if one side is x, then another side would be 9-x (so that they would add up to 18). The area is then A = x(9-x) = 9x - x^2 To find the maximum area, take the first derivative and set it to 0: A' = 9 - 2x 0 = 9 - 2x 2x = 9 x = 9/2 Since the parabola opens down, the maximum area happens when x = 9/2. So if x = 9/2, the other side is 9 - 9/2, or 9/2 - it turns out to be a perfect square! And the area is then (9/2)^2, or 81/4. For the second, you already have an area and you need to find the perimeter. So, lw = 36, and we're trying to find the smallest 2l + 2w. Well, l = 36/w, so the perimeter can be expressed as P = 2l + 2w = 2(36/w) + 2w = 72/w + 2w We can take a derivative and set it to 0 to find the minimum value here: P' = -72/w^2 + 2 0 = -72/w^2 + 2 72/w^2 = 2 w^2 = 36 w = 6 So if w = 6, then l = 6 as well, and the perimeter would then be 24.
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Other answers
A) The greatest possible area of a rectangle with a given perimeter is a SQUARE. Therefore, for an 18 cm. perimeter the square has a side of 4.5 cm. and so the area is 20.25 sq. cm.... B) The rectangle with the least possible perimeter for a given area is also a SQUARE. Therefore, for an area of 36 sq. cm., the side is 6 cm. and so the perimeter must be 24 cm....
genex^adz
p=18 so, l+b=9 l=b-9 area, a=b*(b-9) a=b^2-9b differntiate da=2b-9 for maximum area 2b-9=0 so, b=4.5 l=4.5 so a=4.5*4.5 = 20.25 sqcm next question l*b=36 b=36/l p= 2*(l+(36/l)) differentiate dp=2-72/l^2 2- 72/l^2=0 l^2=36 l=6 so, b=6 p=12*2 perimeter-24 cm solved!!
samuraijackabhi
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