The sum of the 1st 50 terms ofan arithmetic seq.=100. the common difference is increased by 3 what is new sum?
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The sum of the first 50 terms of an arithmetic sequence is 100. If the common difference (d) is increased by 3, what is the new sum?
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Answer:
Actually the new sum is not just 100 + 49(3). It is S= 100 + (1+2+3+...+49)*3 = 100 + (50)(49)/2 *3 = 100 + 3675 = 3775
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Other answers
the new sum = 100+49(3) = ...
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