What is the order of the people in charge of a ship?

How far away does a rocket ship need to be away from a neutron star in miles to safely orbit the neutron star?

• If you were in a rocket ship and you wanted to orbit a neutron star how far away would you have to orbit it and how fast would you have to travel. The fastest a rocket ship can travel is 27,000 miles per hour I think sorry if this is wrong and a something as soft as a marsh mellow would be accelerated to around 100,000 miles per hour to the surface, if it just appeared at near the surface of the neutron star. So travelling at 27,000 how far away from the neutron star would you have to be to safely orbit with a person on board the rocket ship. Also the rocket ship has to be inside the gravitational time dilated area radius of space time the neutron star creates. So this rocket ship can time travel into the future using gravitational time dilation. Can it be done because I asked a question before a long time ago and a few people on yahoo answers said yes it was possible for the rocket ship to orbit a typical neutron star. But I was not specific enough. I forgot to say the rocket ship had to be inside the curvature of space the neutron star creates, in order for the rocket ship to time travel into the future with gravitational time dilation. So is it possible for a rocket ship to do this because the fastest rocket ship can only go 27,000 miles per hour and I do not know how far the radius of the curvature of space time is from the surface of a typical sized neutron star to the end point where the curvature of space time ends where there is no gravitational time dilation. Could you also tell me the distance in miles the curvature of space time is in, in miles from a typical neutron star's surface to the end point radius where space time is no longer curved and time does not slow down. Thank you for your answer, and sorry if this question is not completely accurate.

• Answer:

  If the neutron star has 1 solar mass and the acceptable maximum tide is 1 standard gravity per meter gradient, then the minimum distance is about 3.68 billion meters, or 2.29 million miles. You'd probably want to be even further out though, since that's still pretty stretchy. The tide becomes 1 (m/sec²)/m at a distance of 11.5 billion meters, or 7.16 million miles. G = 6.674e-11 m³ kg⁻¹ sec⁻² M = 1.989e30 kg T = GM( 1/r₁² − 1/r₂² ) / (r₂−r₁) r = distance in meters T = tide in (m/sec²)/m If r₂ = r₁+1, then T/GM = [ 1/r₁² − 1/(r₁+1)² ] r₁² + r₁ − GM/T = 0 r₁ = −1/2 + √(1 + 4GM/T) / 2 With MKS units, you can approximate the tide across a gradient of 1 meter as the gravitational acceleration at that distance divided by one meter. T = GM/r² r = √(GM/T)