How do I make a tow rope?

A skier pulled by a tow rope up a frictionless ski slope that makes an angle of 12° with the horizontal. The r?

• A skier pulled by a tow rope up a frictionless ski slope that makes an angle of 12° with the horizontal. The rope moves parallel to the slope with a constant speed of 1.0 m/s. The force of the rope does 890 J of work on the skier as the skier moves a distance of 7.6 m up the incline. (a) If the rope moved with a constant speed of 2.0 m/s, how much work would the force of the rope do on the skier as the skier moved a distance of 7.6 m up the incline? b) At what rate is the force of the rope doing work on the skier when the rope moves with a speed of 1.0 m/s? (c) At what rate is the force of the rope doing work on the skier when the rope moves with a speed of 2.0 m/s? Any help and suggestions? Please and thank you :)

• Answer:

  My best suggestion for these kinds of problems is to draw a picture and label, label, label! I'll try to explain how to do that, so I'm sorry if it is not very clear. Because the problem starts with the picture needed for the problem in letter b, that's the problem I will start with to hopefully avoid confusion. Letter c is a continuation of the problem in a, so they will have pictures that look exactly alike. (b) *What they are really asking for in letters b and c is how much power is being used.* Draw a straight, horizontal line. Then draw a second line angling upwards that is connected to the first, making an acute angle (less than 90 degrees). Label the inside of the angle as 12 degrees. (This measurement does not have to be accurate at all, it is just being used to visualize the problem.) On the top line of the angle, (the line that is not horizontal,) draw an arrow tip at the end of the line to show which direction the the rope is being pulled. Label the top line as 1.0 m/s to show the speed. Next to that picture, write down what you know and what you need to find out: distance (d) = 7.6 m velocity (v) = 1.0 m/s time (t) = 7.6 s (this is something you have to assume because the skier is moving 1 m for every s) work (w) = 890 J power (P) = ? To find the power, you need the formula for power. Write down this as well. P = w/t (power equals work divided by time) Last but not least, you plug and chug. Simple algebra using the order of operations. (PEMDAS) P = 890 J / 7.6 s Your answer will be in watts, and the unit label is J/s. I can't remember how you would calculate work for letter a, but the picture would look the same, except that the arrow tipped line would be labeled as 2 m/s, not 1 m/s. You would do the same thing in letter c that you do in letter b, but with the value for work as calculated in letter a. Sorry I couldn't do the whole thing. Hope this helps.