How to add new view at the top of an existing view in Android?

What is wrong with this Java code [BlueJ] ?

• I want to make it into a executable file but there is a error coming in the 28th line...) expected...wtf ? import java.io.*; public class STA_Manager { private String name; private int rollno; public void main (String args[]) throws IOException { BufferedReader br=new BufferedReader (new InputStreamReader (System.in)); int choice; System.out.println("\f\n\n\n\t\t\t MAIN MENU "); System.out.println("\n\t\t\t 1. Add new member "); System.out.println("\n\t\t\t 2. View existing members "); System.out.println("\n\t\t\t 3. Exit "); System.out.print("\n\t\t\t Choose [1/2/3] : "); choice=Integer.parseInt(br.readLine()); switch (choice) { case 1 : addmember(); break; case 2 : viewexisting(); break; case 3 : exit(); break; default: main(String args[]); break; } } private void addmember () throws IOException { BufferedReader br=new BufferedReader (new InputStreamReader (System.in)); int choice; System.out.println("\f\n\n\n\t\t\t ADD NEW MEMBER "); System.out.print("\n\t\t\t Name : "); name=br.readLine(); System.out.print("\n\t\t\t Roll No : "); rollno=Integer.parseInt(br.readLine()); System.out.print("\n\t\t\t Please press 1 and then <Enter> to continue : "); choice=Integer.parseInt(br.readLine()); switch (choice) { case 1: main(String args[]); break; default: System.out.print("\n\t\t\t Please press 1 and then <Enter> to continue : "); choice=Integer.parseInt(br.readLine()); } } private void viewexisting () throws IOException { BufferedReader br=new BufferedReader (new InputStreamReader (System.in)); int choice; System.out.println("\f\n\n\n\t\t\t VIEW EXISTING MEMBERS "); System.out.println("\n\t\t\t 1. "+name+":"+rollno); System.out.print("\n\t\t\t Please press 1 and then <Enter> to continue : "); choice=Integer.parseInt(br.readLine()); switch (choice) { case 1: main(String args[]); break; default: System.out.print("\n\t\t\t Please press 1 and then <Enter> to continue : "); choice=Integer.parseInt(br.readLine()); } } private void exit () throws IOException { } }

• Answer:

  You can not call main() recursively, just one of the rules I don't know why. Maybe try an infinite loop while(1) enclosing your switch case. You do after all have exit() on case 3. Better yet look up events and listeners. I suspect that because main is the entry point into the code there is something happening behind the scene to run a new program. It would be interesting to make a program that only has main(){} and see how big it compiles to wouldn't it?