C++.. program that allows the user to enter 4 characters.rogram must check if the string is a palindrome?

if you allow to use string than you can easily do it by using inbuilt function strcpy and strrev int main() { char a[5],b[5]; gets(a); strcpy(b,a); strrev(b); if(strcmp(b,a)==0) cout<<"String is palindrome"; }

Sounds like you want people to do your homework for you! Why don't you start learning about arrays and strings? Palindrome program is one of the simplest ones once you know the concepts. Let me give you a hint for your program. First read the entire string into an array. Use two "for loops", one from left to right of string and other right to left. And compare each array element for both loops to see if it is equal. Something like for(int i=0;i<leng;i++) for(j=leng-1;j>0;j--) a[i] = a[j]; a => string array leng => string length, calculated using the "strlen()" function. All a[i] and a[j] should be equal for a string with even number of characters. For odd number of characters, one center element will be left after all a[i]=a[j] I think this hint, and some study of arrays and strings should be sufficient to write the code yourself. If you get errors, post your code here for help.

See below for about the simplest way I can do it. Beware of the hint. Maybe you're being encouraged to use a second char array, but you don't need to. A good thing for you to try now is to make this work for a char array of any length. #include <iostream> #include <string> #include <sstream> using namespace std; const unsigned N = 4; int main(int argc, char *argv[]) { char a[N]; bool inputOk = false, isPalindrome = true; string line; stringstream ss; cout << "Enter " << N << " chars: "; do { getline(cin,line); ss.clear(); ss.str(line); inputOk = (ss >> a[0] >> a[1] >> a[2] >> a[3]); if (inputOk == false) { cout << "invalid input, try again ..." << endl << "> "; } } while (inputOk == false); for (unsigned i = 0, j = N-1; (i < j) && (isPalindrome == true); i++,j--) { isPalindrome = (a[i] == a[j]); } cout << "is "; if (isPalindrome == false) cout << "not "; cout << "palindrome." << endl; return 0; }