How to pass char** in python ctype?

Runtime error when trying to pass varible to function it aborts plz help?

• Runtime error when trying to pass varible to function it aborts plz help? this code appears to work for other people, but not me, I've tried everything and the people who can help me DON'T apparently when my program tries to pass the number variable to the "pass" function, by program aborts, if someone out there could be so kind to help me fix this problem I would greatly apprecaite it. Thnx. #include <iostream> #include <climits> #include <cstring> const char ssz = 77; const char osz = 21; void pass(short num); void pass(char* str); int main(void) { using std::cout; using std::cin; using std::endl; short number; restart: char* string = new char[ssz]; char option[osz]; cout << "Enter in \"number\" or \"string\" wether you want a string" << " to be passed to the\nfunciton or a number\n"; cin.getline(option, osz); if(strcmp(option, "number") == 0 || strcmp(option, "Number") == 0) { cout << "Enter in any number between " << SHRT_MIN << " and " << SHRT_MAX << endl; cin >> number; pass(number); delete [] string; } else if(strcmp(option, "string") == 0 || strcmp(option, "String") == 0) { cout << "Enter in any text no more than " << ssz-1 << " characters long\n"; cin.getline(string, ssz); pass(string); delete [] string; } else { cout << "You need to type in either \"number\" or \"string\" try again,\nPress Enter to continue.\n"; cin.get(); goto restart; delete [] string; } cin.get(); } void pass(short num) { using std::cout; using std::endl; cout << "The number you entered was " << num << " and " << num << " multiplied by 2 = " << num*2 << endl; } void pass(char* str) { using std::cout; cout << "the text you entered was " << str << ",\n" << "which contains exactly " << strlen(str) << " characters" << " in it.\n"; }

• Answer:

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