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Is using `int` more preferable than using `unsigned int`?

Java: im using a loop to print the sum of odd numbers, of an int = i,?

  • Right now my program runs as enter a number: 7 1 + 3 + 5 + 7 + = 16 i need it to run as: ex. enter a number: 7 1+3+5+7=7+5+3+1 i can't figure out how to stop the loop from printing the extra "+" sign and then need to print the function in reverse order. would really appreciate some insight. here is my current code import java.io.*; import java.util.*; public class sumofoddshowloop{ public static void main(String[] args){ System.out.println("Enter a number"); Scanner sc=new Scanner(System.in); int input=sc.nextInt(); int i=0; int sum=0; while (i<input){ i++; if(i%2==1){ sum=i+sum; System.out.print(i + " + ");} } System.out.println(" = " + sum); } }

  • Answer:

    Well, where you typed your "if" block, I would replace: if ( ( i == input ) && ( i % 2 == 1 ) System.out.print(i); else ( i % 2 == 1 ) System.out.print(i + " + "); This way the last number, if divisible by 2, will print only the number and not the +. For any other number, as long as it is divisible by 2, the + will be printed. EDIT: The above solution by The Phlebob is probably an easier way

Jere Kane at Yahoo! Answers Visit the source

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The usual way to handle this is to determine whether a + is needed before putting one out. Since there's no way of telling whether a number is the last number in the sequence until it's too late, you have to go the other direction and put out a + before any number that's not the first number in the sequence. Code that and it will solve your problem. As for the reversal, why not just run through the numbers a second time from high to low?

Dont print directly. put as String values.The following coding will guide you. String Output[]=new String(100); int Count=0; within if(i%2) { Output[Count]=i+"+"; Count=Count+1; } After that , Remove the last '+' Sign int lastIdx = Count- 1;//Get the last index String OriginalSt = Output.substring(0, lastIdx-1);// Now Remove the last '+' Sign //Reverse the String String ReverseSt = new StringBuffer(OriginalSt).reverse().toStr… //Now Print System.out.println( OriginalSt +"="+ReverseSt ); i hope it will help you

To stop the extraneous plus sign: The non-hackish way to do this is to test to see if you're on the last iteration. If you are, don't print out the "+" sign, because you'd only want to print it out if you AREN'T on the last iteration. Given that you know the exit condition, it's relatively easy to determine when you're on the last iteration (it'll just be when i == input or i == input-1). The hackish way to do this is to store the output to a string, and then output the string in one go. That is, instead of: while (...) { out.print(...); } Do: String output = ""; while (...) { output += ...; } out.println(output); For the second approach, right before the print statement, you can truncate the string's last two characters (which will be the space and plus sign). In order to print out the numbers in reverse, you'd basically do the same thing, but run the loop the other way (starting from the top and iterating down to 0).

Just add if else condition after sum = i + sum; sum=i+sum; if(i < input) {System.out.print(i + " + ");} else {System.out.print(i);} -Sany

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